Question

I want to now how do i split a string like
44664212666666 into [44664212 , 666666] or
58834888888888 into [58834, 888888888]
without knowing where the first occurrence of the last recurring digit occurs.
so passing it to a function say seperate(str) –> [non_recurring_part, end_recurring digits]

Answer 1

print re.findall(r'^(.+?)((.)\3+)$', '446642126666')[0][:-1] # ('44664212', '6666')

As pointed out in the comments, the last group should be made optional to handle strings with no repeated symbols correctly:

print re.findall(r'^(.+?)((.)\3+)?$', '12333')[0][:-1] # ('12', '333')
print re.findall(r'^(.+?)((.)\3+)?$', '123')[0][:-1]   # ('123', '')