Question

I want to open an other application using

[[UIApplication sharedApplication]openURL:[[NSURL alloc]initWithString:myString]];

as log as myString is like

NSString *myString=[NSString stringWithFormat:@"testHandleOpenUrl://?%@",@"123"];

it works fine but if I try to use an NSDictionary like

NSString *myString=[NSString stringWithFormat:@"testHandleOpenUrl://?%@",userInfo];

it fails without an error

Hope you can help me.

Answer 1

Try enumerating all the elements in your dictionary and appending those to your URL.

NSMutableString *params = [[[NSMutableString alloc] init] autorelease];

NSEnumerator *keys = [userInfo keyEnumerator];

NSString *name = [keys nextObject];
while (nil != name) {

    [params appendString: name];
    [params appendString: @"="];
    [params appendString: [userInfo objectForKey:name]];

    name = [keys nextObject];

    if (nil != name) {
        [params appendString: @"&"];
    }
}

NSString *myString=[NSString stringWithFormat:@"testHandleOpenUrl://?%@",params];