Question

I want to open dialogbox each time when OpenDialog() method calls each time with its contents.

Function:

function OpenDialog(){
    $("#seeContent").dialog({
                autoOpen: "false",
                stack: "true",
                height: "600",
                width: "700",
                resizable: "false"
            });
}

Function call:

<input type="button" onclick="OpenDialog()">

Note: It works fine while first call, when second call it overrides the first one.

Answer 1

The clone() helps me to create a copy of dialog. Following is my working code.

jQuery("#seeContent").clone().dialog(
            { autoOpen: "false",
              stack: "true",
              height: "600",
              width: "700",
              resizable: "false" }
  });

I posted this answer because i could help others.

Hope, it will helps you. Thanks. !!