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Home/ Questions/Q 908063
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T16:39:20+00:00 2026-05-15T16:39:20+00:00

I want to open word file from my Windows Application in C#. On button

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I want to open word file from my Windows Application in C#.
On button button click i called Process.start() with file name say “Test.doc”.
File name vary according to some situation.

Now as many times i click the button Process started with same file it started many instance of word.

i want it should open a single instance for same file, and if file name changes then only open new instance.

So how can i detect that word is opened with some file name?

Thanks

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  1. Editorial Team
    Editorial Team
    2026-05-15T16:39:21+00:00Added an answer on May 15, 2026 at 4:39 pm

    Use a list that keeps tracks of Processes that are running. So:

    List<Process> processes = new List<Process>();
    

    When you click to open the file:
    a) make sure the list does NOT contain a process with your filename. (traverse the list then look at process.Filename and compare it to the file you’re wanting to open)
    b) if it doesn’t, add your process to the list and then just start the process.

    Then use

    http://msdn.microsoft.com/en-us/library/system.diagnostics.process.exited.aspx

    To know if the process has exited. When it ends, get rid of it from your process list.

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