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Home/ Questions/Q 893249
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T14:11:22+00:00 2026-05-15T14:11:22+00:00

I want to override public boolean equals(Object obj) function, for name and age, in

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I want to override “public boolean equals(Object obj)” function, for name and age, in my class named MyObject whose structure is given below

public class MyObject{
       private String name;
       private int age;
}

How can i ?

@balusC :

What about this ?

vo  = new MyObject() {
                    public boolean equals(Object obj) {
                        return ((MyObject)obj).name().equals(this.getName());

                    }


vo  = new MyObject() {
                    public boolean equals(Object obj) {
                        return ((MyObject)obj).age() == (this.getAge());
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-15T14:11:23+00:00Added an answer on May 15, 2026 at 2:11 pm

    Your question is a bit vague, but if the sole purpose is to have different sorting algorithms depending on what property you’d like to use, then rather use a Comparator.

    public class Person {
        private String name;
        private int age;
    
        public static Comparator COMPARE_BY_NAME = new Comparator<Person>() {
            public int compare(Person one, Person other) {
                return one.name.compareTo(other.name);
            }
        }
    
        public static Comparator COMPARE_BY_AGE = new Comparator<Person>() {
            public int compare(Person one, Person other) {
                return one.age > other.age ? 1
                     : one.age < other.age ? -1
                     : 0; // Maybe compare by name here? I.e. if same age, then order by name instead.
            }
        }
    
        // Add/generate getters/setters/equals()/hashCode()/toString()
    }
    

    which you can use as follows:

    List<Person> persons = createItSomehow();
    
    Collections.sort(persons, Person.COMPARE_BY_NAME);
    System.out.println(persons); // Ordered by name.
    
    Collections.sort(persons, Person.COMPARE_BY_AGE);
    System.out.println(persons); // Ordered by age.
    

    As to the actual equals() implementation, I’d rather let it return true when the both Person objects are techically or naturally identical. You can use either a DB-generated PK for this to compare on technical identity:

    public class Person {
        private Long id;
    
        public boolean equals(Object object) {
            return (object instanceof Person) && (id != null) 
                 ? id.equals(((Person) object).id) 
                 : (object == this);
        }
    }
    

    or just compare every property to compare on natural identity:

    public class Person {
        private String name;
        private int age;
    
        public boolean equals(Object object) {
            // Basic checks.
            if (object == this) return true;
            if (object == null || getClass() != object.getClass()) return false;
    
            // Property checks.
            Person other = (Person) object;
            if (name == null ? other.name != null : !name.equals(other.name)) return false;
            if (age != other.age) return false;
    
            // All passed.
            return true;
        }
    }
    

    Don’t forget to override hashCode() as well when you override equals().

    See also:

    • Object ordering
    • Sorting an ArrayList of objects
    • Overriding equals() and hashCode()
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