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Home/ Questions/Q 3692368
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Editorial Team
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Editorial Team
Asked: May 19, 20262026-05-19T04:15:15+00:00 2026-05-19T04:15:15+00:00

I want to parse a logfile which has 3 entries. It looks like this:

  • 0

I want to parse a logfile which has 3 entries. It looks like this:

Start: foo
Parameters: foo
End: foo

Start: other foo
Parameters: other foo
End: other foo

....

The foo is what I want. It would be nice if the result looks like this:

logs = [
{
  :start=>"foo",
  :parameters=>"foo",
  :end=>"foo"
},
{
  :start=>"other foo",
  :parameters=>"other foo",
  :end=>"other foo"
}
]

I know some regex, but it’s hard for me to understand how I to this over multiple lines.
Thanks!

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-19T04:15:16+00:00Added an answer on May 19, 2026 at 4:15 am
    #!/usr/bin/ruby1.8
    
    require 'pp'
    
    logfile = <<EOS
    Start: foo
    Parameters: foo
    End: foo
    
    Start: other foo
    Parameters: other foo
    End: other foo
    EOS
    
    logs = logfile.split(/\n\n/).map do |section|
      Hash[section.lines.map do |line|
        key, value = line.chomp.split(/: /)
        [key.downcase.to_sym, value]
      end]
    end
    
    pp logs
    # => [{:end=>"foo", :parameters=>"foo", :start=>"foo"},
    # =>  {:end=>"other foo", :parameters=>"other foo", :start=>"other foo"}]
    
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