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Editorial Team
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Asked: 2026-06-07T17:12:02+00:00

I want to parse a part of html page, say my_string = <p>Some text.

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I want to parse a part of html page, say

my_string = """
<p>Some text. Some text. Some text. Some text. Some text. Some text.
   <a href="#">Link1</a>
   <a href="#">Link2</a>
</p>
<img src="image.png" />
<p>One more paragraph</p>
"""

I pass this string to BeautifulSoup:

soup = BeautifulSoup(my_string)
# add rel="nofollow" to <a> tags
# return comment to the template

But during parsing BeautifulSoup adds <html>,<head> and <body> tags (if using lxml or html5lib parsers), and I don’t need those in my code. The only way I’ve found up to now to avoid this is to use html.parser.

I wonder if there is a way to get rid of redundant tags using lxml – the quickest parser.

UPDATE

Originally my question was asked incorrectly. Now I removed <div> wrapper from my example, since common user does not use this tag. For this reason we cannot use .extract() method to get rid of <html>, <head> and <body> tags.

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1 Answer

  1. Editorial Team

    I could solve the problem using .contents property:

    try:
    children = soup.body.contents
    string = ''
    for child in children:
        string += str(item)
    return string
except AttributeError:
    return str(soup)

    I think that ''.join(soup.body.contents) would be more neat list to string converting, but this does not work and I get

    TypeError: sequence item 0: expected string, Tag found

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