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Editorial Team
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Asked: 2026-06-11T08:23:50+00:00

I want to parse an String containing 8 hex-digits (4bytes) but i got an

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I want to parse an String containing 8 hex-digits (4bytes) but i got an NumberFormatException. What is wrong here?

assertThat(Integer.parseInt("FFFF4C6A",16),is(0xFFFF4C6A));
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1 Answer

  1. Editorial Team

    Your number represents a number greater than that assignable to an int. Try:

    Long.parseLong("FFFF4C6A", 16);

    which gives 4294921322.

    From the doc:

    An exception of type NumberFormatException is thrown if any of the following situations occurs:

    • The first argument is null or is a string of length zero.
    • The radix is either smaller than Character.MIN_RADIX or larger than Character.MAX_RADIX.
    • Any character of the string is not a digit of the specified radix, …
    • The value represented by the string is not a value of type int.

    and it’s the 4th case that you’re hitting.

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