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Home/ Questions/Q 7585927
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Editorial Team
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Editorial Team
Asked: May 30, 20262026-05-30T19:17:47+00:00 2026-05-30T19:17:47+00:00

I want to pass a mySQL result from a function and print the data.

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I want to pass a mySQL result from a function and print the data.
How to do so ?

<?php
function showLatestItems()
 {
  $result = $this->query("SELECT aid,name,description,img,amount,strtdate,enddate FROM item WHERE enddate>now()");
  return $result;
/*      while($row=mysql_fetch_array($result))
   echo $row[0].' '.$row[3].' '.$row[1].' '.$row[2].$row[4].$row[5].$row[6].'<br>';
*/
 }
?>
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  1. Editorial Team
    Editorial Team
    2026-05-30T19:17:49+00:00Added an answer on May 30, 2026 at 7:17 pm

    Just trap the result resource and then fetch rows from it. Based on the commented out code, we assume you have wrapped mysql_query() with a class method called query().

    $result = $yourclass->showLatestItems();
    if ($result) {
      $rowset = array();
      while ($row = mysql_fetch_assoc($result)) {
        $rowset[]  = $row;
      }
    }
    
    var_dump($rowset);
    
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