Question

I want to pass an array parameter to a function in bash, and writing some testing code as：

 #!/bin/sh

    function foo {
       a=$1;
       for i in ${a[@]} ; do
          echo $i
       done
    }
    names=(jim jerry jeff)
    foo ${names[@]}

the above code just show jim, rather than the three j*. so my question is:

• why my code doesn’t work
• what’s the right way to do it

Answer 1

For example like this:

my_array[0]="jim"
my_array[1]="jerry"

function foo
{
    #get the size of the array
    n=${#my_array[*]}
    for (( Idx = 0; Idx < $n; ++Idx  )); do
            echo "${my_array[$Idx]}"
    done
}