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Home/ Questions/Q 6131123
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T16:56:15+00:00 2026-05-23T16:56:15+00:00

I want to pass an optional ‘if’ statement to a Python function to be

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I want to pass an optional ‘if’ statement to a Python function to be executed. For example, the function might copy some files from one folder to another, but the function could take an optional condition.

So, for example, one call to the method could say “copy the files from source to dest if source.endswith(".exe")

The next call could be simply to copy the files from source to destination without condition.

The next call could be to copy files from source to destination if today is monday

How do you pass these conditionals to a function in Python?

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  1. Editorial Team
    Editorial Team
    2026-05-23T16:56:16+00:00Added an answer on May 23, 2026 at 4:56 pm

    Functions are objects. It’s just a function that returns a boolean result.

    def do_something( condition, argument ):
       if condition(argument):
           # whatever
    
    def the_exe_rule( argument ):
        return argument.endswith('.exe')
    
    do_something( the_exe_rule, some_file )
    

    Lambda is another way to create such a function

    do_something( lambda x: x.endswith('.exe'), some_file )
    
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