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Home/ Questions/Q 3307416
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Editorial Team
  • 0
Editorial Team
Asked: May 17, 20262026-05-17T21:24:13+00:00 2026-05-17T21:24:13+00:00

i want to pass my php variable in one javascript function. i know it

  • 0

i want to pass my php variable in one javascript function.
i know it seems simple but i don’t know where am i missing something?

    <?php
        while($gg=mysql_fetch_array($lg))
        {
    ?>
        <td id="add_td">
        <?php
        $id = $gg['p_id'];
        echo "<a onclick=cnf('Are you sure you want to delete that?',$id)>"; ?>Delete</a>
        </td>
<?php
        }
?>

and in my javascript function

function cnf(msg,id)
{

     cnf = confirm(msg);
     if(cnf) { 
            parent.location.href = 'p_update.php?d=' + id;          
     }
}

so i need to know on which id that user had clicked so that i will only delete that id from database.
if i try this thing then it showing error on “cnf” function and its saying like “unterminated string literal”?

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  1. Editorial Team
    Editorial Team
    2026-05-17T21:24:14+00:00Added an answer on May 17, 2026 at 9:24 pm
    if $id is not numeric you should write 
    
    <?php
            while($gg=mysql_fetch_array($lg))
            {
        ?>
            <td id="add_td">
            <?php
            $id = $gg['p_id'];
            echo "<a onclick=cnf('Are you sure you want to delete that?','".$id."')>"; ?>Delete</a>
            </td>
    <?php
            }
    ?>
    
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