I want to perform about many find and replace operations on some text. I have a UTF-8 CSV file containing what to find (in the first column) and what to replace it with (in the second column), arranged from longest to shortest.
E.g.:
orange,fruit2
carrot,vegetable1
apple,fruit3
pear,fruit4
ink,item1
table,item2
Original file:
"I like to eat apples and carrots"
Resulting output file:
"I like to eat fruit3s and vegetable1s."
However, I want to ensure that if one part of text has already been replaced, that it doesn’t mess with text that was already replaced. In other words, I don’t want it to appear like this (it matched “table” from within vegetable1):
"I like to eat fruit3s and vegeitem21s."
Currently, I am using this method which is quite slow, because I have to do the whole find and replace twice:
(1) Convert the CSV to three files, e.g.:
a.csv b.csv c.csv
orange 0001 fruit2
carrot 0002 vegetable1
apple 0003 fruit3
pear 0004 fruit4
ink 0005 item1
table 0006 item 2
(2) Then, replace all items from a.csv in file.txt with the matching column in b.csv, using ZZZ around the words to make sure there is no mistake later in matching the numbers:
a=1
b=`wc -l < ./a.csv`
while [ $a -le $b ]
do
for i in `sed -n "$a"p ./b.csv`; do
for j in `sed -n "$a"p ./a.csv`; do
sed -i "s/$i/ZZZ$j\ZZZ/g" ./file.txt
echo "Instances of '"$i"' replaced with '"ZZZ$j\ZZZ"' ("$a"/"$b")."
a=`expr $a + 1`
done
done
done
(3) Then running this same script again, but to replace ZZZ0001ZZZ with fruit2 from c.csv.
Running the first replacement takes about 2 hours, but as I must run this code twice to avoid editing the already replaced items, it takes twice as long. Is there a more efficient way to run a find and replace that does not perform replacements on text already replaced?
One way to do it would be to do a two-phase replace:
The @@1## markers should be chosen so that they don’t appear in the original text or the replacements of course.
Here’s a proof-of-concept implementation in perl: