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Home/ Questions/Q 8476221
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Editorial Team
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Editorial Team
Asked: June 10, 20262026-06-10T18:07:12+00:00 2026-06-10T18:07:12+00:00

I want to perform some arithmetic in unsigned, and need to take absolute value

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I want to perform some arithmetic in unsigned, and need to take absolute value of negative int, something like

do_some_arithmetic_in_unsigned_mode(int some_signed_value)
{
   unsigned int magnitude;
   int negative;
   if(some_signed_value<0) {
       magnitude = 0 - some_signed_value;
       negative = 1;
    } else {
       magnitude = some_signed_value;
       negative = 0;
    }
   ...snip...
}

But INT_MIN might be problematic, 0 – INT_MIN is UB if performed in signed arithmetic.
What is a standard/robust/safe/efficient way to do this in C?

EDIT:

If we know we are in 2-complement, maybe implicit cast and explicit bit ops would be standard? if possible, I’d like to avoid this assumption.

do_some_arithmetic_in_unsigned_mode(int some_signed_value)
{
   unsigned int magnitude=some_signed_value;
   int negative=some_signed_value<0;
   if (negative) {
       magnitude = (~magnitude) + 1;
    }
   ...snip...
}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-10T18:07:14+00:00Added an answer on June 10, 2026 at 6:07 pm

    Conversion from signed to unsigned is well-defined: You get the corresponding representative modulo 2N. Therefore, the following will give you the correct absolute value of n:

    int n = /* ... */;
    
    unsigned int abs_n = n < 0 ? UINT_MAX - ((unsigned int)(n)) + 1U
                               : (unsigned int)(n);
    

    Update: As @aka.nice suggests, we can actually replace UINT_MAX + 1U by 0U:

    unsigned int abs_n = n < 0 ? -((unsigned int)(n))
                               : +((unsigned int)(n));
    
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