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Home/ Questions/Q 546809
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T10:54:22+00:00 2026-05-13T10:54:22+00:00

I want to print out a dictionary, sorted by the key. Sorting the keys

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I want to print out a dictionary, sorted by the key. Sorting the keys is easy in the view, by just putting the keys in a list and then sorting the list. How can I loop through the keys in the template and then get the value from the dictionary.

{% for company in companies %}
    {% for employee, dependents in company_dict.company.items %}
    {% endfor %}
{% endfor %}

(Just made up the example…)
The part that doesn’t work is the “company_dict.company.items” part. I need the “company” to be the value of company. Right now the company prat is looking for a key named “company” not the value of “company” from the loop above.

I’m doing a bit of processing to put the dictionary of dictionaries together. Changing the layout of the data isn’t really an option. I figure the right approach is to write up a template tag, just wanted to know if there was a built-in way I missed.

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  1. Editorial Team
    Editorial Team
    2026-05-13T10:54:22+00:00Added an answer on May 13, 2026 at 10:54 am

    a custom template filter will do the trick.

    from django import template
    register = template.Library()
    
    def dict_get(value, arg):
        #custom template tag used like so:
        #{{dictionary|dict_get:var}}
        #where dictionary is duh a dictionary and var is a variable representing
        #one of it's keys
    
        return value[arg]
    
    register.filter('dict_get',dict_get)
    

    more on custom template filters: http://docs.djangoproject.com/en/dev/howto/custom-template-tags/#howto-custom-template-tags

    in your example you’d do:

    {% for employee, dependents in company_dict|company %}
    
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