I want to print the current working directory and its content. The program will be done in x86, 16bit Intel syntax, DOS Assembly using interrupts. The assembler I will use will be Turbo assembler. Here is my code so far(not much):
ASSUME cs:code, ds:data
data segment
buffer db 64 dup (0) ; buffer for the current directory name
data ends
code segment
start:
mov ax, data ;
mov ds, ax ; move data segment into ds, es registers
mov es, ax ;
mov dl, 0 ; default drive
mov si, offset buffer ; put current directory in buffer
mov ah, 47h ; GET CURRENT DIRECTORY
int 21h
; appending '$' to buffer end
; search until 0 found
mov cx, 64 ; search over all buffer
cld ; starting from the beginning
end_string:
lodsb ; get current byte in al register
cmp al, 0 ; compare it with 0
jne continue ; if not equal jump to continue label
mov al, 36 ; if equal copy 36('$' - ASCII) in al
mov di, si ; set destination index to source index
sub di, 1 ; decrement di
stosb ; store in es:di the value contained in al
mov cx, 1 ; stop looping by setting cx to 1
continue:
loop end_string
; print string obtained
mov dx, offset buffer ; ds:dx - string start
mov ah, 09h ; WRITE STRING TO STANDARD OUTPUT
int 21h
mov ax, 4c00h ; end program with exit code 0
int 21h
code ends
end start
I managed to get it running and display the current working directory. But now I don’t know how to get his child directories and the files contained in the directory. So my question is : how do I get them?
Use the DOS services
FindFirst(0x4e) andFindNext(0x4f) to get a list of entries in the given directory. You can then differentiate subdirectories and files based on the returned attributes.