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Home/ Questions/Q 7756833
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T12:55:26+00:00 2026-06-01T12:55:26+00:00

I want to programmatically modify a bitmap using python but don’t really need a

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I want to programmatically modify a bitmap using python but don’t really need a thorough grounding in the subject, so would like to concentrate on learning just what I need to get the job done.

A good example of the kind of thing I’m after would be a bitmap image of england and it’s counties. This would initially display a black border around all the counties on a white background.

So far so good, but how can I dynamically change the background color of a county?

Off the top of my head I was thinking I might find a flood-fill routine that works similar to a simple paint app. Something that changes all the pixels within an area enclosed by a specified color. I’ve had a quick look at the PIL documentation but didn’t find anything I recognised as a flood fill function?

I don’t yet know exactly what a mask is or how to use it but maybe this is an avenue I should explore. Maybe I could define a mask for each county and then use the mask to guide the fill process? Can masks be defined and stored within the bitmap for later use by my program?

Same goes for paths???

Any help or pointers would be greatly appreciated.

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  1. Editorial Team
    Editorial Team
    2026-06-01T12:55:27+00:00Added an answer on June 1, 2026 at 12:55 pm

    PIL has an undocumented function ImageDraw.floodfill:

    >>> import ImageDraw
    >>> help(ImageDraw.floodfill)
    Help on function floodfill in module ImageDraw:
    
    floodfill(image, xy, value, border=None)
        Fill bounded region.
    

    (Flood-filling should generally be a last resort because it interacts poorly with anti-aliased lines. It is usually better to get the actual boundary data for the counties and then draw a filled polygon. However, PIL doesn’t support anti-aliased line drawing so this advice is useless unless you switch your drawing module to something more capable like PythonMagick or pycairo.)

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