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Home/ Questions/Q 8404659
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Editorial Team
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Editorial Team
Asked: June 9, 20262026-06-09T22:39:18+00:00 2026-06-09T22:39:18+00:00

I want to provide specialized optimizations for allocations done with std::allocator , but if

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I want to provide specialized optimizations for allocations done with std::allocator, but if someone has subclassed it without overriding allocate or deallocate, then I don’t know how to detect whether they’re still using std::allocator or not.

How do I do this?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-09T22:39:19+00:00Added an answer on June 9, 2026 at 10:39 pm

    Assuming they haven’t defined their own allocate and deallocate functions, then one way to test is by testing the value

    is_default_allocator_allocation<allocator_type>::value
    

    to test whether the allocate and deallocate methods are the default ones.

    If they have provided their own functions, then there is no generic way to test.

    This solution does not look at the other methods.
    It can give you occasional false negatives, but should not give false positives.

    My implementation:

    template<class Ax> char (&is_default_deallocate(void (std::allocator<typename Ax::value_type>::*)(typename Ax::pointer, typename Ax::size_type)))[1];
    template<class Ax> char (&is_default_deallocate(void (Ax::*)(typename Ax::pointer, typename Ax::size_type)))[2];
    template<class Ax> char (&is_default_allocate(typename Ax::pointer (std::allocator<typename Ax::value_type>::*)(typename Ax::size_type, void const *)))[1];
    template<class Ax> char (&is_default_allocate(typename Ax::pointer (Ax::*)(typename Ax::size_type, void const *)))[2];
    
    template<class Ax>
    struct is_default_allocator_allocation  // tests allocate() and deallocate()
    {
        static bool const value =
            sizeof(is_default_deallocate<Ax>(&Ax::deallocate)) == sizeof(char)
            && sizeof(is_default_allocate<Ax>(&Ax::allocate)) == sizeof(char);
    };
    
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