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Home/ Questions/Q 8050391
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Editorial Team
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Editorial Team
Asked: June 5, 20262026-06-05T07:04:53+00:00 2026-06-05T07:04:53+00:00

I want to put a lot of filtering in a Bash script, to get

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I want to put a lot of filtering in a Bash script, to get my filtering commands a little shorter:

#before:
$ cat unreadable.log | grep "bla" |[...]| sed "s/blubb//" >>readable.log
#after:
$ cat unreadable.log | the_script_I_m_writing.sh >>readable.log

But how to handle the IO in the bash-script correctly, that the after line can be executed as shown?
As you can see inside the bash-script there will be a lot of simple commands that are piped together. All this piping should just begin with stdin and send the final result out to stdout.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-05T07:04:53+00:00Added an answer on June 5, 2026 at 7:04 am

    cat reads from standard input if no file argument is given.

    #!/usr/bin/env bash
    cat | grep "bla" | sed 's/blubb//'
    

    Alternatively, just write a script that accepts the source file name as argument.

    #!/usr/bin/env bash
    cat "$1" | grep "bla" | sed 's/blubb//'
    

    Use: ./script unreadable.log.


    In this simple case, you can also skip the cat, and just start with grep.

    #!/usr/bin/env bash
    grep "bla" | sed 's/blubb//'
    

    Use:

    # unnecessary cat if it's just a file
    cat file | ./script.sh
    
    # get stdin from file
    ./script.sh < file
    
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