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Home/ Questions/Q 8119543
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Editorial Team
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Editorial Team
Asked: June 6, 20262026-06-06T04:49:48+00:00 2026-06-06T04:49:48+00:00

I want to put an interface down and up every 1 second for 80

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I want to put an interface down and up every 1 second for 80 times, how can I implement this by a bash script?

Something like this?

COUNT = 80
for n in $(seq -w 1 $COUNT); do
    case $n in   
    [1,3,5,7,9....79]*) # I don't know how to represent the odd value only
       ifconfig veth1 down
       sleep 1
       ;;
    [2,4,6,8,10....80]*)
       ifconfig veth1 up
       sleep 1
       ;;
   esac
done 
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-06T04:49:51+00:00Added an answer on June 6, 2026 at 4:49 am
    COUNT=40
    for n in $(seq -w 1 $COUNT); do
      ifconfig veth1 down
      sleep 1
      ifconfig veth1 up
      sleep 1
    done
    

    Or if you really want to count to 80:

    COUNT=80
    for n in $(seq -w 1 $COUNT); do
      case $n in
        *[13579])
         ifconfig veth1 down
         ;;
        *)
         ifconfig veth1 up
         ;;
      esac
      sleep 1
    done
    
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