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Home/ Questions/Q 3489278
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Editorial Team
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Editorial Team
Asked: May 18, 20262026-05-18T11:22:34+00:00 2026-05-18T11:22:34+00:00

I want to read in mulitple files from a directory and store each value

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I want to read in mulitple files from a directory and store each value in a unique variable so I can print it out later with a descriptive header. The file names have a common prefix, but are unique.

I know how to open up one file, but is there an efficient way to open up many files? or do i have open unique file handles for each one? thanks.

Filenames have a common prefix like (abc_*):

abc_foo_dir
abc_bar.dat1.20101208
abc_bar.dat2.20101209

Example opening up first file:

open FILE, "< /home/test/data/abc_foo_dir";
while (<FILE>) {
my $line = $_;
chomp($line);
print "$line\n";
}
close FILE;
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-18T11:22:35+00:00Added an answer on May 18, 2026 at 11:22 am

    You say “store each value in a unique variable”, but this is actually a task for a hash table.

    my %file_contents;
    foreach my $filename (qw(...filenames here... or use a glob to fetch them))
    {
        open my $fh, '<', $filename or die "Cannot open $filename: $!";
        local $/;   # enable slurp mode
    
        # read in the entire contents of the file and store in the hash
        $file_contents{$filename} = <$fh>;
    
        # this would close automatically when going out of scope,
        # but it's nice to be explicit
        close $fh;
    }
    

    You can iterate through all the keys later with keys %file_contents, but if you aren’t familiar with how to work with hashes, I urge you to read perldoc perldata and perldoc perlsyn.

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