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Home/ Questions/Q 8602385
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T02:04:24+00:00 2026-06-12T02:04:24+00:00

I want to read the content of a URL with the following code :

  • 0

I want to read the content of a URL with the following code :

        myUrl=new URL(url);
        stream=myUrl.openStream();

but the second line of code triggers an “android.os.NetworkOnMainThreadException” without any other explanation.

I work under Androïd 4 and I can add this code used to work with Androïd 2.3.3.

Any idea?

Thanks in advance for the time you will spend trying to help me.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-12T02:04:25+00:00Added an answer on June 12, 2026 at 2:04 am

    So problem is that application attempts to perform a networking operation on main thread and this is not allowed.

    For your goal i recommend to you use AsyncTask and do your work in background Thread.

    Here is example from my little app:

    protected InputStream doInBackground(String... params) {
    
                int contentLength = 0;
                int buffLength = 0;
                int progress = 0;
                InputStream inputStream = null;
                try {
    
                    URL url = new URL(params[0]);
                    HttpURLConnection urlConntection = (HttpURLConnection) url.openConnection();
                    urlConntection.setRequestMethod("GET");
                    urlConntection.setAllowUserInteraction(false);
                    urlConntection.setInstanceFollowRedirects(true);
                    urlConntection.connect();
                    if (urlConntection.getResponseCode() == HttpURLConnection.HTTP_OK) {
                        contentLength = urlConntection.getContentLength();
                        progressDialog.setMax(contentLength);
                        inputStream = urlConntection.getInputStream();
    
                        while ((buffLength = inputStream.read(MAX_BUFFER)) != -1) {
                            try {
                                Thread.sleep(1);
                                progress += buffLength;
                                DataTransmitted data = new DataTransmitted(progress, contentLength);
                                publishProgress(data);
                            }
                            catch (InterruptedException ex) {
                                Log.e(this.getClass().getName(), ex.getMessage());
                            }
                        }
    
                    }
                    else {
                        throw new IOException("No response.");
                    }
    
                }
                catch (MalformedURLException ex) {
                    Log.e(this.getClass().getName(), ex.getMessage());
                }
                catch (IOException ex) {
                    errorDialog.show();
                }
                return inputStream;
            }
    

    Or here is similar topic:

    • Download a file with Android, and showing the progress in a
      ProgressDialog
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