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Home/ Questions/Q 6783991
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T16:56:12+00:00 2026-05-26T16:56:12+00:00

I want to replace all occurences of a pattern in a string by another

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I want to replace all occurences of a pattern in a string by another string. For example, lets convert all “$” to “!”:

"$$$" -> "!!!"

Plain string.replace replaces only the first match:

"$$$".replace("$", "!"); // gives "$!!"

and regexes force me to escape to special chars

"$$$".replace(/\$/g, "!"); // Pattern is now full of backslashes!

Is it possible to do the global replacement without having to manually escape the special characters? I have a bunch of patterns is a part of my code and I think readability would suffer if had to escape all of them by hand.

I’m expecting either a trick that directly does what I want or at least a way to convert a string to an excaped form useable by new RegExp

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  1. Editorial Team
    Editorial Team
    2026-05-26T16:56:12+00:00Added an answer on May 26, 2026 at 4:56 pm

    There is no standard regexp escape function in Javascript.

    You can write your own (source) or get it from your library (dojo example)

    function escape(s) {
        return s.replace(/[-/\\^$*+?.()|[\]{}]/g, '\\$&')
    };
    

    This allows us to create the custom regex object at runtime

    function replace_all(string, pattern, replacement){
        return string.replace( new RegExp(escape(pattern), "g"), replacement);
    }
    
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