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Home/ Questions/Q 406637
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Editorial Team
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Editorial Team
Asked: May 12, 20262026-05-12T17:30:57+00:00 2026-05-12T17:30:57+00:00

I want to replicate the following c code in python ctypes: main() { long

  • 0

I want to replicate the following c code in python ctypes:

main() {
  long *ptr = (long *)0x7fff96000000;
  printf("%lx",*ptr);
}

I can figure out how to call this memory location as a function pointer but not just do a normal dereference:

from ctypes import *
"""
>>> fptr = CFUNCTYPE(None, None)
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "/usr/lib/python2.6/ctypes/__init__.py", line 104, in CFUNCTYPE
    class CFunctionType(_CFuncPtr):
TypeError: Error when calling the metaclass bases
    item 1 in _argtypes_ has no from_param method
"""
fptr = CFUNCTYPE(None, c_void_p) #add c_void_p since you have to have an arg
fptr2 = fptr(0x7fff96000000)
fptr2(c_void_p(0))
#python: segfault at 7fff96000000 ip 00007fff96000000

Since there it is a segfault with the instruction pointer pointing to this memory location it is successfully calling it. However I can’t get it to just read the memory location:

ptr = POINTER(c_long)
ptr2 = ptr(c_long(0x7fff96000000))
#>>> ptr2[0]
#140735709970432
#>>> hex(ptr2[0])
#'0x7fff96000000'
#>>> ptr2.contents
#c_long(140735709970432)
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-12T17:30:57+00:00Added an answer on May 12, 2026 at 5:30 pm

    ctypes.cast.

    >>> import ctypes
    >>> c_long_p = ctypes.POINTER(ctypes.c_long)
    >>> some_long = ctypes.c_long(42)
    >>> ctypes.addressof(some_long)
    4300833936
    >>> ctypes.cast(4300833936, c_long_p)
    <__main__.LP_c_long object at 0x1005983b0>
    >>> ctypes.cast(4300833936, c_long_p).contents
    c_long(42)
    
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