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Home/ Questions/Q 8194479
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Editorial Team
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Editorial Team
Asked: June 7, 20262026-06-07T04:50:21+00:00 2026-06-07T04:50:21+00:00

I want to restart a thread for some use, for example in the below

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I want to restart a thread for some use, for example in the below code.

class Ex13 implements Runnable {
    int i = 0;

    public void run() {
        System.out.println("Running " + ++i);
    }

    public static void main(String[] args) throws Exception {
        Thread th1 = new Thread(new Ex13(), "th1");
        th1.start();
            //th1.join() 
        Thread th2 = new Thread(th1);
        th2.start();
    }
}

When I’m executing the above program , some time i’m getting the output as
Running 1
Running 2
and some time i’m getting only
Running 1
After few run i’m getting only
Running 1 as output.
I’m totally surprise about this behavior. Can any one help me understand this.
if I put the join() then i’m getting only Running 1.

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  1. Editorial Team
    Editorial Team
    2026-06-07T04:50:22+00:00Added an answer on June 7, 2026 at 4:50 am

    You reuse Thread instance, not Runnable. Thread overwrites its run() method to

    public void run() {
        if (target != null) {
            target.run();
        }
    }
    

    Where target is the Runnable that you give to the constructor. besides that, Thread has an exit() method that is called by the VM, and this method sets target to null (the reason is this bug). So if your first thread has the chance to finish its execution, its run() method is pretty much empty. Adding th1.join() proves it.

    If you want to keep some state, you need to keep reference to your Runnable instance, not the Thread. This way run() method will not be altered.

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