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Home/ Questions/Q 8608939
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T03:44:44+00:00 2026-06-12T03:44:44+00:00

I want to run fast Matlab algorithms over Matrices by ignoring zero-elements. In the

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I want to run fast Matlab algorithms over Matrices by ignoring zero-elements.

In the past I just worked with a very slow double-for-loop e.g.

for i = 1 : size(x,1)
   for j = 1 : size(x,2)
        if x(i,j) ~= 0
            ... do something with x(i,j)
        end
     end
end

But how can I make the matrix operation on the whole matrix x?
E.g. how can I run

x(i,j) = log(x(i,j)) if x>0 else 0    <-- pseudo code

in Matlab on the whole matrix without for loops?

Finally I want to rewrite lines like

result = sum(sum((V.*log(V./(W*H))) - V + W*H));

with ignoring zeros.

I just need to understand the concept.
In case of need I could also use NaN instead of zero, but I didn’t find e.g. the function

nanlog()
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  1. Editorial Team
    Editorial Team
    2026-06-12T03:44:46+00:00Added an answer on June 12, 2026 at 3:44 am

    You can use NaN as a temporary and make use of the fact that log(NaN) = NaN, like so:

    x(x==0) = NaN;
    y = log(x);
    y(isnan(y)) = 0;
    

    alternatively, you can use logical indexing:

    x(x~=0) = log(x(x~=0));
    

    or, if you want to preserve x,

    y = x;
    y(y~=0) = log(y(y~=0));
    

    For the example you provide, you can just do

    result = nansum(nansum((V.*log(V./(W*H))) - V + W*H));
    

    assuming that V == 0 is the problem.

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