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Home/ Questions/Q 9162893
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Editorial Team
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Editorial Team
Asked: June 17, 20262026-06-17T14:19:19+00:00 2026-06-17T14:19:19+00:00

I want to see the real C source code of the functions — its

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I want to see the “real” C source code of the functions — its real implementation in the gcc and clang compiler. I mean “real” because I look at in the header file but I see only a prototype and something that seems like an extension.

For example, let’s say that I want the code of the standard C tmpnam() function. It’s defined in the stdio.h header (by standard — I know that only its prototype must be defined there; the code itself can come from any (better chosen by the compiler writer) header file). But what I can see only is

/* Generate a temporary filename.  */
extern char *tmpnam (char *__s) __THROW __wur;
__END_NAMESPACE_STD

Where is the code of the function that make it work? That’s I’m looking for. Similarly, I don’t find it in the clang compiler.
If possible, can someone explain why the compiler writer choose this model? Doesn’t it leave the code explicit in the respective header file? Is it some “trick” to perform some type of optimization, or something like that?

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  1. Editorial Team
    Editorial Team
    2026-06-17T14:19:21+00:00Added an answer on June 17, 2026 at 2:19 pm

    You can try to get the source code of glibc or any similar C library implementation. That should have the code you are looking for. You can also browse the source code of glibc online.

    As for the reasoning, its basic “You dont see what you dont need to see” reasoning. There is no need to see the implementation, just the interface to the library.

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