Question

I want to select elements that have similar incrementally-based names. Is there shorter notation to do the same thing?

$('#galnav1,#galnav2,#galnav3,#galnav4,#galnav5,#galnav6,#galnav7,#galnav8,#galnav9,').each(function(){
    ... 
});

Answer 1

How about this one:

$('[id^=galnav]');

$('[id^=galnav]').filter(function() {
    return /v\d$/.test($(this).attr('id'));
});