Home/ Questions/Q 7048971
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Asked: 2026-05-28T02:57:22+00:00

I want to show my div (wrapper) when body is loaded. This is my

  • 0

I want to show my div (wrapper) when body is loaded. This is my code:

$("div.wrapper").hide();
$('body').load(function() {
    $('.wrapper').show();
});

But my code not work. What is my mistake?

Share

Leave an answer

You must login to add an answer.

Need An Account,

1 Answer

  1. Editorial Team

    Description

    .ready() Specify a function to execute when the DOM is fully loaded.

    So make your div invisible using css and make it visible using jQuery.

    Sample

    Html

    <div class="wrapper" style="display:none">
   <!-- your content -->
</div>

    jQuery

    $(document).ready(function() {
   $('.wrapper').show();
});

    Complete Sample

    <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN">
<html>
    <head>
        <title></title>

        <script type="text/javascript" src="PathToYourJqueryJsFile" />
        <script type="text/javascript">
            $(document).ready(function () {
                $('.wrapper').show();
            });
        </script>
    </head>
    <body>
        <div class="wrapper" style="display:none">
        <!-- your content -->
        </div>  
    </body>
</html>

    More Information

    • 0