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Home/ Questions/Q 601455
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T16:43:02+00:00 2026-05-13T16:43:02+00:00

I want to specify in a header file that the input to a function

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I want to specify in a header file that the input to a function will be an iterator_range, and the iterator can be dereferenced to obtain an int. What is the best way to do this? I do not want to say iterator_range<std::vector<int>::iterator> as this binds the implementation to use std::vector<int>.

Would appreciate any ideas to specify the function the best way.

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  1. Editorial Team
    Editorial Team
    2026-05-13T16:43:02+00:00Added an answer on May 13, 2026 at 4:43 pm

    A common way to do this is to make the range a template parameter and then let the usage you make of it be the “concept check”:

    template<class SinglePassRange>
    void func(SinglePassRange const & nums)
    {
       typedef typename boost::range_iterator<SinglePassRange>::type It;
       for(It it = nums.begin(), e = nums.end(); it != e; ++it)
       {
           int i = *it; 
           // Do something with your int
       } 
    }
    

    This won’t compile if your range does not contain ints (or something convertible to int) so there’s no need to add any further constraints to the interface. But if you really want you can add a concept check at the begining of your function (it will provide better error messages to your clients):

    BOOST_CONCEPT_ASSERT(
        (boost::Convertible<typename boost::range_value<SinglePassRange>::type,
                            int>));
    

    Finally, if you don’t want to make your function a template then I think that you’ll have to cope with taking a boost::iterator_range<std::vector<int>::iterator> but in that case I see no advantage with respect to taking a simple std::vector&.

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