Question

I want to split a String into alternating words. There will always be an even number.

e.g.

val text = "this here is a test sentence"

should transform to some ordered collection type containing

"this", "is", "test"

and

"here", "a", "sentence"

I’ve come up with

val (l1, l2) = text.split(" ").zipWithIndex.partition(_._2 % 2 == 0) match {
  case (a,b) => (a.map(_._1), b.map(_._1))}

which gives me the right results as two Arrays.

Can this be done more elegantly?

Answer 1

scala> val s = "this here is a test sentence"
s: java.lang.String = this here is a test sentence

scala> val List(l1, l2) = s.split(" ").grouped(2).toList.transpose
l1: List[java.lang.String] = List(this, is, test)
l2: List[java.lang.String] = List(here, a, sentence)