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Home/ Questions/Q 9258609
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Editorial Team
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Editorial Team
Asked: June 18, 20262026-06-18T12:27:01+00:00 2026-06-18T12:27:01+00:00

I want to store a 64bit (8 byte) big integer to a nodejs buffer

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I want to store a 64bit (8 byte) big integer to a nodejs buffer object in big endian format.

The problem about this task is that nodejs buffer only supports writing 32bit integers as maximum (with buf.write32UInt32BE(value, offset)). So I thought, why can’t we just split the 64bit integer?

var buf = new Buffer(8);

buf.fill(0) // clear all bytes of the buffer
console.log(buf); // outputs <Buffer 00 00 00 00 00 00 00 00>

var int = 0xffff; // as dezimal: 65535

buf.write32UInt32BE(0xff, 4); // right the first part of the int
console.log(buf); // outputs <Buffer 00 00 00 00 00 00 00 ff>

buf.write32UInt32BE(0xff, 0); // right the second part of the int
console.log(buf); // outputs <Buffer 00 00 00 ff 00 00 00 ff>

var bufInt = buf.read32UInt32BE(0) * buf.read32UInt32BE(4);
console.log(bufInt); // outputs 65025

As you see this nearly works. The problem is just splitting the 64bit integer and finding the missing 510 at reading it. Would somebody mind showing the solutions for these two issues?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-18T12:27:02+00:00Added an answer on June 18, 2026 at 12:27 pm

    I think what you are looking for is:

    var bufInt = (buf.readUInt32BE(0) << 8) + buf.readUInt32BE(4);
    

    Shift the first number by 8 bits and add (instead of multiplying), wich returns 65535


    EDIT

    Another way to write would be:

    var buf = new Buffer(8);
    buf.fill(0);
    
    var i = 0xCDEF; // 52719 in decimal
    
    buf.writeUInt32BE(i >> 8, 0); //write the high order bits (shifted over)
    buf.writeUInt32BE(i & 0x00ff, 4); //write the low order bits
    
    console.log(buf); //displays: <Buffer 00 00 00 cd 00 00 00 ef>
    
    var bufInt = (buf.readUInt32BE(0) << 8) + buf.readUInt32BE(4);
    console.log(bufInt); //displays: 52719
    
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