Home/ Questions/Q 98727
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Asked: 2026-05-11T00:15:06+00:00

I want to store a string in memory and read it later: $$->desc.constant->base.id =

  • 0

I want to store a string in memory and read it later:

$$->desc.constant->base.id =  (char*)malloc(200); sprintf($$->desc.constant->base.id, '%f', $1); printf('->%s\n', $$->desc.constant->base.id); //LINE A printf('->%i\n', $$->desc.constant); //LINE B  //SOME OTHER CODE  //Then, later on in a function call:  printf('%i', expr->desc.constant); // LINE D printf('%s', expr->desc.constant->base.id); // LINE C

Although Line B and Line D show the same address, the printf in Line C fails with a Segmentation fault. What am I missing?

Any help would really be appreciated!

Share

Leave an answer

You must login to add an answer.

Need An Account,

1 Answer

  1. printf('->%i\n', $$->desc.constant); //LINE B

    That is invalid. As you show the line prior to it that constant is actually a pointer, you cannot treat it as if it were of type int. They don’t necassarily have the same sizeof and alignment. Use the format used for void*. It will output memory addresses properly:

    printf('->%p\n', (void*)$$->desc.constant); //LINE B
    • 0