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Home/ Questions/Q 6920701
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T10:10:54+00:00 2026-05-27T10:10:54+00:00

I want to store image on mysql database by php as blob type, but

  • 0

I want to store image on mysql database by php as blob type, but the following error is shown:

Warning: getimagesize(3272) [function.getimagesize]: failed to open
stream: No such file or directory in F:\XAMPP\htdocs\0412\form.php on
line 15

I use the following code:

  if($_POST['upload'] == 'upload' ) {
     // connect to database
     mysql_connect("localhost","root","") or die(mysql_error());
     mysql_select_db("image") or die(mysql_error());

     // name of the upload image
     $name = addslashes($_FILES['uploadImage']['name']);
     // image
     $image = addslashes( file_get_contents( $_FILES['uploadImage']['tmp_name']) );
     $size = getimagesize($_FILES['uploadImage']['size']);


     if( $size == FALSE ) {
        echo "NO image selected $form";  
     }
     else {
        move_uploaded_file($_FILES['uploadImage']['tmp_name'],"UploadImage/".$name);

        if( !( $result = mysql_query(" INSERT INTO image VALUES ('','$name','$image') ") ) ) {
           echo "uploading image problem $form";    
        }

        } 
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T10:10:56+00:00Added an answer on May 27, 2026 at 10:10 am

    This line:

    $size = getimagesize($_FILES['uploadImage']['size']);
    

    Needs to be:

    $size = getimagesize($_FILES['uploadImage']['tmp_name']);
    

    Instead. You’re tripping up over the fact that getimagesize() gets the size of the image from the image data itself. All you’ve passed to it is a number indicating it’s upload size in bytes.

    The correct example above opens the image from it’s temporary location, which is held in tmp_name.

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