Question

I want to take the difference between lists x and y:

>>> x = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
>>> y = [1, 3, 5, 7, 9]  
>>> x - y
# should return [0, 2, 4, 6, 8]

Answer 1

Use a list comprehension to compute the difference while maintaining the original order from x:

[item for item in x if item not in y]

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If you don’t need list properties (e.g. ordering), use a set difference, as the other answers suggest:

list(set(x) - set(y))

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To allow x - y infix syntax, override __sub__ on a class inheriting from list:

class MyList(list):
    def __init__(self, *args):
        super(MyList, self).__init__(args)

    def __sub__(self, other):
        return self.__class__(*[item for item in self if item not in other])

Usage:

x = MyList(1, 2, 3, 4)
y = MyList(2, 5, 2)
z = x - y