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Home/ Questions/Q 7612819
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T02:00:42+00:00 2026-05-31T02:00:42+00:00

I want to test and see if everything in an array passes my check,

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I want to test and see if everything in an array passes my check, here is how I am presently doing it and my fantasy code which crashes the compiler.

Current:

def mylist = [1,2,3,4]
def presumeTrue = true
mylist.each{
  if(it<0)presumeTrue=false
}
if(presumeTrue)println "Everything was greater than 0!!"

Fantasy:

def mylist = [1,2,3,4]
if(mylist*>0)println "Everything was greater than 0, but this sugar doesn't work."

Is there a correct way to apply an if test to everything in a list one one line?

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  1. Editorial Team
    Editorial Team
    2026-05-31T02:00:43+00:00Added an answer on May 31, 2026 at 2:00 am

    Use the every method:

    myList.every { it > 0 }
    

    The operator you were trying to use is “spread dot”, which is *. (not *). You’d need to use the method name (compareTo), which takes an argument. But map isn’t what you’re trying to do.

    You’re not trying to apply the method to all of mylist‘s members, you’re trying to aggregate the result of applying the method to all the members, more like:

    mylist.inject(true) { acc, n -> acc && n > 0 }
    
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