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Home/ Questions/Q 6755003
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T13:20:54+00:00 2026-05-26T13:20:54+00:00

I want to test whether a request parameter is greater then 12 or not

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I want to test whether a request parameter is greater then 12 or not JavaScript.

It always gives the alert “lesser” even when I change the value of q to 12.

The current URL is: www.test.com?id=2

How can this be done in JavaScript?

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  1. Editorial Team
    Editorial Team
    2026-05-26T13:20:55+00:00Added an answer on May 26, 2026 at 1:20 pm

    Your code works. If it returns true, then it alerts greater. Although you should be adding semicolons at the end of statements. Your code would look like this:

    var q = 14;
    if (q > 10)
        alert('greater');
    else
        alert('Lesser');
    

    Working demo

    As said by Derek, if q === 10, then it would alert ‘Lesser’ because 10 is not more than 10.

    EDIT: Here, you have 2 options. Either use something like PHP to make q equal to the number like this:

    q = <?php echo $_GET['id']; ?>
    

    Note that using this would open your site up to all kinds of XSS, so if you decide to go this way, learn a bit about security, and don’t rush into uploading it to a live website.

    Or, if you want to to do it using JavaScript only, then do it like this:

    q = location.href.substring(location.href.indexOf('id=')+3); //3 is the length of id=
    q = parseInt(q, 10); //With substring, you get a string, so you have to parse it
    

    The 10 is the radix parameter, avoiding you getting strange numbers for inputs such as 010 (would be 8 without the parameter).

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