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Home/ Questions/Q 626927
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T19:28:21+00:00 2026-05-13T19:28:21+00:00

I want to truncate absolute values below an epsilon to 0, e.g., Truncate[{-3, -2,

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I want to truncate absolute values below an epsilon to 0, e.g.,

Truncate[{-3, -2, -1, 0, 1, 2, 3}, 1.5] -> {-3, -2, 0, 0, 0, 2, 3}

I guess I could write a function using Scan[] and If[], but is there a more idiomatic “one-liner” way of doing it in Mathematica?

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  1. Editorial Team
    Editorial Team
    2026-05-13T19:28:21+00:00Added an answer on May 13, 2026 at 7:28 pm

    The built in function Chop is almost exactly what you’re looking for (it does work on lists, as in your example). One potential surprise is that it doesn’t chop (truncate) integers, only floating point numbers. So for your example to work as you might expect, first convert your list to floating point with the N function:

    Chop[N@{-3, -2, -1, 0, 1, 2, 3}, 1.5] -> {-3., -2., 0, 0, 0, 2., 3.}
    

    As Ramashalanka shows, to do this sort of thing more generally, I recommend:

    If[Abs[#]<1.5&, 0, #]& /@ {-3, -2, -1, 0, 1, 2, 3}
    

    Ie, a lambda function mapped over the list.

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