Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 7522341
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 30, 20262026-05-30T02:29:41+00:00 2026-05-30T02:29:41+00:00

I want to unzip a zip file. I have the zip data as bytes.

  • 0

I want to unzip a zip file. I have the zip data as bytes. I used the below code to unzip the zip file. But I can read the names from files in the zip file. But the output data is corrupted. I think I am reading the whole data in ZipInputStream. The how can i read each file data? Plz help me
Thanks..

ByteArrayInputStream binput = new ByteArrayInputStream(zipeddatainbyte);
    ZipInputStream mzipstream = new ZipInputStream(binput);
    File f2 = new File("/sdcard/Unziped Data/");
    f2.mkdirs();
    ZipEntry entry;
    FileOutputStream out;
    byte[] bout=null;
    try {
        while ((entry = mzipstream.getNextEntry()) != null) {
            System.out.println("entry: " + entry.getName() + ", "
                    + entry.getSize());
            bout=new byte[(int) entry.getSize()];
            mzipstream.read(bout);
            out = new FileOutputStream("/sdcard/Unziped Data/"+entry.getName());
            out.write(bout);
            out.close();



        }
    } catch (IOException e) {

        e.printStackTrace();
    }
  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-30T02:29:43+00:00Added an answer on May 30, 2026 at 2:29 am

    You should not trust entry.getSize(), but try to read till the end of the stream for each ZipEntry and control what is actually read. This applies not only to ZipInputStreams but also to any Java InputStream. This snippet is extracted from here:

    ZipEntry entrada;
    while (null != (entrada=zis.getNextEntry()) ){
       System.out.println(entrada.getName());
    
       FileOutputStream fos = new FileOutputStream(entrada.getName());
       int leido;
       byte [] buffer = new byte[1024];
       while (0<(leido=zis.read(buffer))){
          fos.write(buffer,0,leido);
       }
       fos.close();
       zis.closeEntry();
    }
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I have one zip file that i want unzip .the size of this file
I want to unzip a file and this works fine system('unzip File.zip'); But I
I have zip file and I want to know which library can handle it?
I have the function below, but the problem is that the zip file will
Basically, I have a jar file that i want to unzip to a specific
I want to unzip a .zip file using VBScript, only it's always a new
want to have a Hyperlink-Button in a gridView in which I can display a
I have am trying to unzip a file via SSH, I require a case
I want to uncompress zipped file say, files.zip , to a directory that is
I have this as my input content = 'abc.zip'\n I want to take out

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.