Question

I want to update data to mysql database i know the query. query is not a problem..

The Problem i am facing is that how should i send id page to other page..

lets suppose i am on page skill_edit.php?id=7
and i click update button then it goes to skills.php from skill_edit.php using POST method of form.

but now how can i send id of page or even id of row in table to “skills.php”

My Database:

My Form in skill_edit.php

     <form class="form-horizontal row-fluid" method="post" action="skills.php">

        <?php //Skill Name ?>
        <div class="form-row control-group row-fluid">
          <label class="control-label span3" for="with-placeholder">Skill Name</label>
          <div class="controls span7">
            <input type="text" name="skill_name" id="with-placeholder" class="row-fluid" value="<?php echo $showskillname; ?>">
          </div>
        </div>

       <?php //Skill Description ?>
        <div class="form-row control-group row-fluid">
          <label class="control-label span3" for="elastic-textarea">Skill Desc <span class="help-block">My Skill Description</span> </label>
          <div class="controls span7">
            <textarea name="skill_desc" rows="3" style=" height:80px;"  class="row-fluid autogrow" id="elastic-textarea"><?php echo $showskilldesc; ?></textarea>
          </div>
        </div>

        <?php //Selecting Language ?>
        <div class="form-row control-group row-fluid">
          <label class="control-label span3">Select with search</label>
          <div class="controls span7">
            <select name="skill_rating" data-placeholder="Choose a Language...." class="chzn-select">
              <option value="<?php echo $showskillrating; ?>"><?php echo $showskillrating; ?></option>
              <option value="1">1 Star</option>
              <option value="2">2 Star</option>
              <option value="3">3 Star</option>
              <option value="4">4 Star</option>
              <option value="5">5 Star</option>
            </select>
          </div>
        </div>


       <?php //Buttons ?>
        <div class="form-actions row-fluid">
          <div class="span7 offset3">
            <button name="updatebtn" style=" float:left; margin-left:40px;" type="submit" class="btn btn-primary">Save changes</button>
            <button formaction="skills.php" style=" float:right; margin-right:40px;" type="submit" class="btn btn-secondary">Cancel</button>
          </div>
        </div>
      </form>

my skill.php page on which i get the data

if(isset($_POST['updatebtn']))
{
$updatedskillname = mysql_real_escape_string($_POST['skill_name']);
$updatedskilldesc = mysql_real_escape_string($_POST['skill_desc']);
$updatedskillrating = mysql_real_escape_string($_POST['skill_rating']);
$last_updated = mysql_real_escape_string(date('F j, Y, g:i a'));

$update=update_skill($updatedskillname, $updatedskilldesc, $updatedskillrating, $last_updated);
}

Here is the inside of the function

//Update Skill
//skills.php
function update_skill($updatedskillname, $updatedskilldesc, $updatedskillrating, $last_updated)
{
        $query="UPDATE cv_skills SET
                            skill_name='$updatedskillname',
                            skill_desc='$updatedskilldesc',
                            skill_rating='$updatedskillrating',
                            last_updated='$last_updated' WHERE skill_id='$pageid'";
$result=mysql_query($query);
$error=mysql_error();

return $error;
}

so how can i get skill_id in my query??

Answer 1

There’s a couple possible ways you can do this but one would be to do:

<form class="form-horizontal row-fluid" method="post" action="skills.php?id=<?php echo $_GET['id']; ?>">

This will then post back to itself with the id still in tact. The other way would be you could use a hidden field so you POST the id back to the form.

Hidden:

<input type="hidden" name="id" value="<?php echo $_GET['id']; ?>">