Question

i want to update query from array.the problem is when i ran the code, the updated data in the database just the first data..

example..

the array consist of integer type = [1,2]

when i ran the code, the data in the database just ran the first data (only 1)..how can i fix this?

PHP file

$query_edit_paket = "select nama_menu from menu where id_menu = 149 ";
        $query_exec_edit_paket = mysql_query($query_edit_paket) or die(mysql_error());  
        $nama_menu_query = reset(mysql_fetch_assoc($query_exec_edit_paket));

     $_fbexclude = mysql_query("select id_paket from detail_paket where menu_paket = '$nama_menu_query' ");
    $fbexcludearray = array();
    while ($row = mysql_fetch_assoc($_fbexclude)) {
      $fbexcludearray[] = $row['id_paket'];
    }

    $excludes = implode(',', $fbexcludearray);
    echo $excludes;

    for($i=0;$i<count($excludes);$i++)  
    {           
        if($excludes != "")  
        {           
            $strSQL = "update paket set ketersediaan_paket ='kosong' ";  
            $strSQL .="WHERE id_paket = '$excludes' ";  
            $objQuery = mysql_query($strSQL);
        }
    } 

thanks!!

Answer 1

Try using IN

change

$strSQL .="WHERE id_paket = '$excludes' ";  

to

$foo = '';
for($i=0; $i < count($fbexcludearray); $i++){
  $foo.= $i == 0? $fbexcludearray[$i]: ','.$fbexcludearray[$i];
}
    $strSQL .="WHERE id_paket IN ($foo) ";