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Home/ Questions/Q 9118121
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Editorial Team
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Editorial Team
Asked: June 17, 20262026-06-17T05:04:08+00:00 2026-06-17T05:04:08+00:00

I want to upload a file via FTP upload in a form. <html> <body>

  • 0

I want to upload a file via FTP upload in a form.

<html>
  <body>
    <form enctype="multipart/form-data" action="upload_file.php" method="POST">
      <input type="hidden" name="MAX_FILE_SIZE" value="100000" />
      Choose a file to upload: <input name="uploadedfile" type="file" /><br />
      <input type="submit" value="Upload File" />
    </form>
  </body>
</html>

Here is the PHP file:

<?php

$ftp_server = "xxx";
$ftp_username   = "xxx";
$ftp_password   =  "xxx";

// setup of connection
$conn_id = ftp_connect($ftp_server) or die("could not connect to $ftp_server");

// login
if (@ftp_login($conn_id, $ftp_username, $ftp_password))
{
  echo "conectd as $ftp_username@$ftp_server\n";
}
else
{
  echo "could not connect as $ftp_username\n";
}

$file = $_FILES["file"]["name"];
$remote_file_path = "/home/www/lifestyle69/import/".$file;
ftp_put($conn_id, $remote_file_path, $file, FTP_ASCII);
ftp_close($conn_id);
echo "\n\nconnection closed";

?>

The FTP connection connects successfully but the file is nowhere.

Can anybody help me?

Thanks!

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-17T05:04:09+00:00Added an answer on June 17, 2026 at 5:04 am

    Because you have <input name="uploadedfile" type="file" />:

    $file = $_FILES["file"]["name"]; // wrong
    $file = $_FILES["uploadedfile"]["name"]; // right
    

    Because you need the filename of the temporary copy stored by PHP, which exists on the server:

    ftp_put($conn_id, $remote_file_path, $file, FTP_ASCII); // wrong
    ftp_put($conn_id, $remote_file_path, $_FILES["uploadedfile"]["tmp_name"],
            FTP_ASCII); // right
    

    Refer to the PHP documentation for more information about $_FILES.

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