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Home/ Questions/Q 3495452
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Editorial Team
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Editorial Team
Asked: May 18, 20262026-05-18T12:07:42+00:00 2026-05-18T12:07:42+00:00

I want to use LZO to compress a array of int or byte. So

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I want to use LZO to compress a array of int or byte. So I need to copy the int array to a *char then I will compress and save to file. And after i need do reverse operation. I will open the file read it with *Char and the decompress to array of int.

I don’t want to do a look in the *char to convert each int. Is the any way to do this quickily?

char *entrada;
int *arrayInt2;
int arrayInt1[100];
int ctr;

for(ctr=0;ctr<=100; ctr++)
{
    arrayInt1[ctr] = ctr;
} 

entrada = reinterpret_cast<char *>(arrayInt1);
arrayInt2 = reinterpret_cast<int *>(entrada);

return 0;

I want something like this. Is this correct?
Thanks

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-18T12:07:43+00:00Added an answer on May 18, 2026 at 12:07 pm

    You can treat the integer array directly as a (binary) character buffer and pass it to your compression function:

    char *buffer = reinterpret_cast<char *>(my_int_array);
    

    And similarly when you decompress into a character buffer, you can use it as an integer array:

    int *array = reinterpret_cast<int *>(my_char_buffer);
    

    Make sure that you keep track of the original length of the integer array and that you don’t access invalid indices.

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