Question

I want to use my custom PHP function CalculateAge which takes 3 parameters (day, month and year) inside a SQL UPDATE. However, I need to pass the SQL variables to the function, and I don’t know how to do it. Here’s what it looks like (note that bday, bmonth and byear are “users” table columns).

mysql_query("UPDATE users SET age=".CalculateAge(bday,bmonth,byear)."");

Answer 1

You can’t pass the mysql values into the function like that. You would have to do a SELECT to get the values, fetch the row, pass them into the function, and then INSERT that value.

I would suggest that instead of updating the age, you should store the person’s birthday since it never changes. When you want to show their age, just do the math.