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Home/ Questions/Q 6090873
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T12:15:48+00:00 2026-05-23T12:15:48+00:00

I want to use numpy.savetxt() to save an array of complex numbers to a

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I want to use numpy.savetxt() to save an array of complex numbers to a text file. Problems:

  • If you save the complex array with the default format string, the imaginary part is discarded.
  • If you use fmt='%s', then numpy.loadtxt() can’t load it unless you specify dtype=complex, converters={0: lambda s: complex(s)}. Even then, if there are NaN’s in the array, loading still fails.

It looks like someone has inquired about this multiple times on the Numpy mailing list and even filed a bug, but has not gotten a response. Before I put something together myself, is there a canonical way to do this?

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  1. Editorial Team
    Editorial Team
    2026-05-23T12:15:49+00:00Added an answer on May 23, 2026 at 12:15 pm

    It’s easier and saves a few temporary arrays to just reinterpret the array as a real array.

    Saving:

    numpy.savetxt('outfile.txt', array.view(float))
    

    Loading:

    array = numpy.loadtxt('outfile.txt').view(complex)
    

    If you prefer to have real and imaginary part on the same line in the file, you can use

    numpy.savetxt('outfile.txt', array.view(float).reshape(-1, 2))
    

    or

    array = numpy.loadtxt('outfile.txt').view(complex).reshape(-1)
    

    respectively.

    (Note that neither view() nor reshape() copies the array — it will just reinterpret the same data in a different way.)

    Addendum from the question asker:

    If you want to save more than one complex array in the same file, you can do it like so:

    numpy.savetxt('outfile.txt', numpy.column_stack([
        array1.view(float).reshape(-1, 2),
        array2.view(float).reshape(-1, 2),
    ]))
    
    array1, array2 = numpy.loadtxt('outfile.txt', unpack=True).view(complex)
    

    The reshaping is necessary because numpy.view() doesn’t operate on strided arrays.

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