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Home/ Questions/Q 3244754
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Editorial Team
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Editorial Team
Asked: May 17, 20262026-05-17T18:35:20+00:00 2026-05-17T18:35:20+00:00

I want to use the following code just to check the input. #include <stdio.h>

  • 0

I want to use the following code just to check the input.

#include <stdio.h>
#include <iostream>
#include <ctype.h>

int main() 
  {
    int number1; 

    puts("Enter number 1 please:");
    scanf_s("%d",&number1);

    if (isdigit(number1)) 
    {
      puts("Input is correct.");

    }
    else 
    {
      puts("Your input is not correct. Enter a number please.");
    }

      std::cin.get();
      std::cin.get();


  }

Unfortunately it doensn’t work. I type in a digit and my response is “Your input is not…”. Any suggestions where the problem is?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-17T18:35:21+00:00Added an answer on May 17, 2026 at 6:35 pm

    Your problem is in the use of isdigit. Compare this code:

    int main() 
    {
    int number1; 
    
    puts("Enter number 1 please:");
    scanf_s("%d",&number1);
    printf("You entered %d\n", number1);
    if (isdigit(number1)) 
    {
      puts("Input is correct.");
    
    }
    else 
    {
      puts("Your input is not correct. Enter a number please.");
    }
    
      std::cin.get();
      std::cin.get();
    
    
    }
    

    When you enter a valid number, this is reflected in the successful printf of this number.

    You should check the return of scanf, not use isdigit, such as this sample code:

    int main() 
    {
    int number1; 
    
    puts("Enter number 1 please:");
    if (scanf_s("%d",&number1))        
      puts("Input is correct.");
    else
      puts("Your input is not correct. Enter a number please.");
    
    std::cin.get();
    std::cin.get();
    }
    

    I believe that for more than one field, you will need to check the return value of scanf more closely than simply zero or one.

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