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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T06:42:45+00:00 2026-05-13T06:42:45+00:00

I want to use XSL to convert XML to another XML The input xml

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I want to use XSL to convert XML to another XML

The input xml contains the following element

<ViewSideIndicator>0</ViewSideIndicator>

which need to be converted to the following

<ImageViewDetail ViewSideIndicator="Front"/>

in the input file, if the value is “0”, then it should be “Front” in the output
and if the value is “1”, then it should be “Back” in the output

I know that we can use <xsl:choose> to make the value based on a decision, but i’m not sure how to do it for this case.

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  1. Editorial Team
    Editorial Team
    2026-05-13T06:42:46+00:00Added an answer on May 13, 2026 at 6:42 am

    In the template (assuming that the current source context is the ViewSideIndicator element):

    <ImageViewDetail>
        <xsl:attribute name="ViewSideIndicator">
            <xsl:choose>
                <xsl:when test="text()='0'">Front</xsl:when>
                <xsl:when test="text()='1'">Back</xsl:when>
            </xsl:choose>
        </xsl:attribute>
    </ImageViewDetail>
    
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