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Home/ Questions/Q 6828371
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T22:22:30+00:00 2026-05-26T22:22:30+00:00

I want to validate user-input. If the number user has entered is greater than

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I want to validate user-input. If the number user has entered is greater than 3, then it should throw error ‘Too high’, if it is lesser than 0.15, then ‘Too low’. If it’s between 3 and 0.15, then it should show ‘Okay’.

The problem with my code is that if the user has entered a negative value, it still shows ‘Okay’ to him. It seems regardless of what the user enters, it shows ‘Okay’.

This is the code:

$('#submit').click(function(e) {
        vel = $('#vel').val();
        validVel(vel);
});

function validVel(v) {

    if (v > 3) {
        $('.er').fadeIn(2000);
        var error = "Too High";
        $('.er').text(error);   
    }
    else if (v < 0.15) {
        $('.er').fadeIn(2000);
        var error = "Too Low";
        $('.er').text(error);   
    }
    else {
        $('.er').fadeIn(2000);
        var error = "Okay";
        $('.er').text(error);
    }


}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-26T22:22:31+00:00Added an answer on May 26, 2026 at 10:22 pm

    You need a parseFloat in your function to ensure the equality checks are valid. As pointed out by WilQu you should also include an isNaN test –

    function validVel(v) {
    
        fv = parseFloat(v);
    
        if (fv > 3) {
            $('.er').fadeIn(2000);
            var error = "Too High";
            $('.er').text(error);   
        }
        else if (fv < 0.15) {
            $('.er').fadeIn(2000);
            var error = "Too Low";
            $('.er').text(error);   
        }
        else if (isNaN(fv)) {
            $('.er').fadeIn(2000);
            var error = "Not a number";
            $('.er').text(error);   
        }   
        else {
            $('.er').fadeIn(2000);
            var error = "Okay";
            $('.er').text(error);
        }
    } 
    

    Demo – http://jsfiddle.net/AyhRS/7

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