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Home/ Questions/Q 6741265
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T11:42:15+00:00 2026-05-26T11:42:15+00:00

I want to write a asynchronous socket server in C, but before I do

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I want to write a asynchronous socket server in C, but before I do I’m doing some research. Looking at the select() socket example shown here: http://www.gnu.org/s/hello/manual/libc/Server-Example.html#Server-Example I can see that the example program will only accept one client per select loop (if I’m reading it right). So if there are 20 clients and two more try to connect, will it only accept the 21st client then process the other 20 (worst case, assuming all 20 others require reading) and THEN accept the 22nd? Would it be better if I break the loop after accepting a client so it can select() again and take care of all pending clients before processing connected ones? Or does that defeat the purpose of using select()? Thanks.

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  1. Editorial Team
    Editorial Team
    2026-05-26T11:42:16+00:00Added an answer on May 26, 2026 at 11:42 am

    The server pattern shown in the example you linked to is fine; there isn’t any significant problem introduced by the loop only accepting one socket per iteration.

    The key point to keep in mind is that in a well-designed select() loop, the only place the process should ever block is inside the select() call. In particular, if coded correctly, the server will never block inside send(), recv(), or accept(). It’s best to set all sockets to non-blocking mode (via fcntl(fd, F_SETFL, O_NONBLOCK)) in order to guarantee this behavior.

    Given that, the precise ordering of “which clients get serviced first within any particular event loop iteration” doesn’t matter, because all clients’ sockets get handled very soon after they have data ready-for-read (or buffer space ready-for-write), and all new connections get accepted quickly.

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