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Asked: May 11, 20262026-05-11T01:24:41+00:00 2026-05-11T01:24:41+00:00

I want to write a function that returns the nearest next power of 2

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I want to write a function that returns the nearest next power of 2 number. For example if my input is 789, the output should be 1024. Is there any way of achieving this without using any loops but just using some bitwise operators?


Related: Algorithm for finding the smallest power of two that's greater or equal to a given value is a C++ question. C++20 introduced std:bit_ceil which lets the compiler do whatever’s optimal for the target system, but nothing equivalent is yet available in portable ISO C for bit-scan, popcount or other common bit operations that most CPUs have. Portable C code has to be less efficient and/or more complicated.

Given an integer, how do I find the next largest power of two using bit-twiddling? is a language-agnostic version of the question with some C++11 and 17 constexpr using GNU extensions.

Answers to this question don’t need to be portable; fast versions for various platforms are useful.

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  1. 2026-05-11T01:24:41+00:00Added an answer on May 11, 2026 at 1:24 am

    Check the Bit Twiddling Hacks. You need to get the base 2 logarithm, then add 1 to that. Example for a 32-bit value:

    Round up to the next highest power of 2

    unsigned int v; // compute the next highest power of 2 of 32-bit v  v--; v |= v >> 1; v |= v >> 2; v |= v >> 4; v |= v >> 8; v |= v >> 16; v++; 

    The extension to other widths should be obvious.

    An answer on Given an integer, how do I find the next largest power of two using bit-twiddling? presents some explanation of how it works, and examples of the bit-patterns for a couple inputs.

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